How do you do this?
Please help

Answers :I anticipate the acknowledgment is

y = (x+2)(x-4) + 8

or y = x^2-2x

Answers :y = a(x + 2)(x - 4).

y = a(2)(-4) = -8a => a = 1.

y = (x + 2)(x - 4).

Equation: y = x^2 - 2x + 8.

-John

Answers :y = (x+2)(x-4)

is a acceptable start. It has the appropriate roots. Let x=0, admitting and you get

y=(2)(-4) = -8

instead of 8. So you charge to accumulate the accomplished by -1

y = -1(x+2)(x-4)
y = -1(x^2 - 2x - 8)
y = -x^2 + 2x + 8

Answers :If those are the routes, it agency (x + 2) and (x - 4) anatomy its factors:

(x + 2)(x - 4) = x^2 - 2x - 8

This will cantankerous at -8. You wish 8, so cast it around:

-1 * (x^2 - 2x - 8) = -x^2 + 2x + 8

Answers :Ax^2 + Bx +C = 0
(work backwards to ample that in ... 0 will become y, or added accurately 'y = 0')
(x+2)(x-4) = 0
x^2 +2x -4x -8 = 0
x^2 -2x -8 = 0

y = x^2 -2x -8 (when x = 0 this will boldness to y = -8, this is instead of the +8 accepted by the x=0, y=8 advertence point .. (0,8) so we alter it by adding by -1, leaving)
y = 2x-x^2+8
which simplifies to:
y = (x-4)(-x-2)

ANS: y = (x-4)(-x-2)

Please help!
I charge to acquisition the parametric equations of the curve:
(x^2)+(y-1)^2 = 9 for:

a) starting at the point (3,1) and traveling about already clockwise
b) starting at (3,1) and traveling about 4 times counterclockwise
c) starting at (0,4) and traveling about center counterclockwise

Thanks again!