this is the problem:

1. 0.0000056

Answers :5.6 x 10^-6 which is five-point-six times ten to-the-negative-sixth (because you accept to move the decimal abode 6 places to the appropriate to get 5.6)

if it was 5600000 your acknowledgment wouldve been 5.6 x 10^6 (because you had to move six spaces to the left)

so if you move appropriate the backer is negative
if u move left, the backer is positive

Answers :5.6 times 10 to the -6th power

Answers :5.6 x 10^-6

(five-point-six times ten to-the-negative-sixth)

Answers :I anticipate it is already in accurate notation.

Answers :just calculation the places from the decimal point to the point at which you accept a individual chiffre in the 'ones' place. In your archetype 0.0000056 there are 6 places in which you could put a decimal point which would accomplish the amount 5.6.
Now you accept to add the ability of 10 to the number, in your archetype that ability is 6 and back you confused the decimal point to the RIGHT, it is a abrogating ability of 10 so you end up with
5.6 times 10 to the abrogating 6th power
or 5.6^6
or 5.6E6
all of which say the aforementioned thing

Answers :To plan it out, address a dot on a section of cardboard and again the amount afterwards it. So for 0.0000056, change it to .00000056, and again calculation how abounding times the dot has to jump over a aught afore it is in amid two amount that are not 0. Seeing as the amount is abate than 1, you apperceive that how anytime abounding all-overs there were, you will charge to put a '-' afore it.

So the acknowledgment is 5.6 x 10^-6

Answers :To acknowledgment this problem, you charge to move the decimal point in amid the 5 and the 6. Then, calculation the amount of places that you confused the decimal. For example, in this problem, you move the point 6 places to the right.

So, you would accept 5.6*10^-6 (the ^-6 agency that the -6 would be an backer of 10)

Answers :this is so simple...

just calculation the chiffre afterwards the point...

and it is 7.....

then put point in amid endure two digit...
5.6
and accumulate it by
10^-(7-1) = 10^-6

so acknowledgment is 5.6 x 10^-6

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