The escape acceleration from the apparent of the moon is 1.9 km/s. Compute the complete temperature (in K) at which the rms acceleration of atomic oxygen will be acceptable to acquiesce it to escape from the moon.

I've been application the equation: T= (v^2*M)/3R
I adapted my v into 1900m/s
M to .32kg/mol

Can anyone advice me out?

Answers :It is OK except : M = 32 x 10 ˇ-3 kg/mol

A Little Leaguer asks her mother to accomplish her a home bowl for a sandlot baseball game. According to her encyclopedia, an offical bowl is fabricated from a aboveboard authoritative two 12 inch askew cuts. What is the breadth of the ancillary of the orginal square?